ID | Title | Difficulty | |
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1116. Print Zero Even Odd
Medium
LeetCode
Concurrency
Problem
You have a function printNumber that can be called with an integer parameter and prints it to the console.
- For example, calling printNumber(7) prints 7 to the console.
You are given an instance of the class ZeroEvenOdd that has three functions: zero, even, and odd. The same instance of ZeroEvenOdd will be passed to three different threads:
- Thread A: calls zero() that should only output 0’s.
- Thread B: calls even() that should only output even numbers.
- Thread C: calls odd() that should only output odd numbers.
Modify the given class to output the series “010203040506…” where the length of the series must be 2n.
Implement the ZeroEvenOdd class:
- ZeroEvenOdd(int n) Initializes the object with the number n that represents the numbers that should be printed.
- void zero(printNumber) Calls printNumber to output one zero.
- void even(printNumber) Calls printNumber to output one even number.
- void odd(printNumber) Calls printNumber to output one odd number.
Example 1:
Input: n = 2
Output: "0102"
Explanation: There are three threads being fired asynchronously.
One of them calls zero(), the other calls even(), and the last one calls odd().
"0102" is the correct output.
Example 2:
Input: n = 5
Output: "0102030405"
Code
class ZeroEvenOdd {
int n;
Semaphore semaphoreEven, semaphoreOdd, semaphoreZero;
public ZeroEvenOdd(int n) {
this.n = n;
semaphoreZero = new Semaphore(1);
semaphoreEven = new Semaphore(0);
semaphoreOdd = new Semaphore(0);
}
// printNumber.accept(x) outputs "x", where x is an integer.
public void zero(IntConsumer printNumber) throws InterruptedException {
int numTimes = this.n;
boolean printOdd = true;
for(int i = 0; i < numTimes; i++){
semaphoreZero.acquire();
printNumber.accept(0);
//print the next number
if(printOdd)
semaphoreOdd.release();
else
semaphoreEven.release();
printOdd = !printOdd; //flip it!
}
}
public void even(IntConsumer printNumber) throws InterruptedException {
int numTimes = this.n / 2;
int nextEvenNum = 2;
for(int i = 0; i < numTimes; i++){
semaphoreEven.acquire();
printNumber.accept(nextEvenNum);
nextEvenNum += 2;
semaphoreZero.release();
}
}
public void odd(IntConsumer printNumber) throws InterruptedException {
int numTimes = (int)Math.ceil((double)this.n / 2);
int nextOdd = 1;
for(int i = 0; i < numTimes; i++){
semaphoreOdd.acquire();
printNumber.accept(nextOdd);
nextOdd += 2;
semaphoreZero.release();
}
}
}
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