ID | Title | Difficulty | |
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1179. Reformat Department Table
Easy
LeetCode
Database
Problem
Table: Department
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| revenue | int |
| month | varchar |
+-------------+---------+
(id, month) is the primary key of this table.
The table has information about the revenue of each department per month.
The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
Write an SQL query to reformat the table such that there is a department id column and a revenue column for each month.
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input:
Department table:
+------+---------+-------+
| id | revenue | month |
+------+---------+-------+
| 1 | 8000 | Jan |
| 2 | 9000 | Jan |
| 3 | 10000 | Feb |
| 1 | 7000 | Feb |
| 1 | 6000 | Mar |
+------+---------+-------+
Output:
+------+-------------+-------------+-------------+-----+-------------+
| id | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
+------+-------------+-------------+-------------+-----+-------------+
| 1 | 8000 | 7000 | 6000 | ... | null |
| 2 | 9000 | null | null | ... | null |
| 3 | null | 10000 | null | ... | null |
+------+-------------+-------------+-------------+-----+-------------+
Explanation: The revenue from Apr to Dec is null.
Note that the result table has 13 columns (1 for the department id + 12 for the months).
Code
select id,
sum(case when month = 'jan' then revenue else null end) as Jan_Revenue,
sum(case when month = 'feb' then revenue else null end) as Feb_Revenue,
sum(case when month = 'mar' then revenue else null end) as Mar_Revenue,
sum(case when month = 'apr' then revenue else null end) as Apr_Revenue,
sum(case when month = 'may' then revenue else null end) as May_Revenue,
sum(case when month = 'jun' then revenue else null end) as Jun_Revenue,
sum(case when month = 'jul' then revenue else null end) as Jul_Revenue,
sum(case when month = 'aug' then revenue else null end) as Aug_Revenue,
sum(case when month = 'sep' then revenue else null end) as Sep_Revenue,
sum(case when month = 'oct' then revenue else null end) as Oct_Revenue,
sum(case when month = 'nov' then revenue else null end) as Nov_Revenue,
sum(case when month = 'dec' then revenue else null end) as Dec_Revenue
from department
group by id
order by id
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