ID | Title | Difficulty | |
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339. Nested List Weight Sum
Medium
LeetCode
Depth-First Search, Breadth-First Search
Problem
Given a nested list of integers, return the sum of all integers in the list weighted by their depth.
Each element is either an integer, or a list – whose elements may also be integers or other lists.
Example 1:
Input: [[1,1],2,[1,1]]
Output: 10
Explanation: Four 1's at depth 2, one 2 at depth 1.
Example 2:
Input: [1,[4,[6]]]
Output: 27
Explanation: One 1 at depth 1, one 4 at depth 2, and one 6 at depth 3; 1 + 4*2 + 6*3 = 27.
Code
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
* // Constructor initializes an empty nested list.
* public NestedInteger();
*
* // Constructor initializes a single integer.
* public NestedInteger(int value);
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // Set this NestedInteger to hold a single integer.
* public void setInteger(int value);
*
* // Set this NestedInteger to hold a nested list and adds a nested integer to it.
* public void add(NestedInteger ni);
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
class Solution {
public int depthSum(List<NestedInteger> nestedList) {
int res = 0;
Queue<NestedInteger> queue = new LinkedList<>();
for(NestedInteger n : nestedList) {
queue.add(n);
}
int level = 1;
while(!queue.isEmpty()) {
int size = queue.size();
for (int i = 0; i < size; i++) {
NestedInteger n = queue.poll();
if (n.isInteger()) {
res += n.getInteger() * level;
} else {
List<NestedInteger> ll = n.getList();
queue.addAll(ll);
}
}
level += 1;
}
return res;
}
}
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