ID | Title | Difficulty | |
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509. Fibonacci Number
Easy
LeetCode
Math, Dynamic Programming, Recursion, Memoization
Problem
The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,
F(0) = 0, F(1) = 1
F(n) = F(n - 1) + F(n - 2), for n > 1.
Given n, calculate F(n).
Example 1:
Input: n = 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.
Example 2:
Input: n = 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.
Example 3:
Input: n = 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.
Constraints:
- 0 <= n <= 30
Code
class Solution {
public int fib(int n) {
if(n == 0) return 0;
if(n == 1) return 1;
int num1 = 0;
int num2 = 1;
for(int i = 2; i <= n; i++) {
int sum = num1 + num2;
num1 = num2;
num2 = sum;
}
return num2;
}
}
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