ID | Title | Difficulty | |
---|---|---|---|
Loading... |
624. Maximum Distance in Arrays
Medium
LeetCode
Array, Greedy
Problem
You are given m arrays, where each array is sorted in ascending order.
You can pick up two integers from two different arrays (each array picks one) and calculate the distance. We define the distance between two integers a and b to be their absolute difference |a - b|.
Return the maximum distance.
Example 1:
Input: arrays = [[1,2,3],[4,5],[1,2,3]]
Output: 4
Explanation: One way to reach the maximum distance 4 is to pick 1 in the first or third array and pick 5 in the second array.
Example 2:
Input: arrays = [[1],[1]]
Output: 0
Constraints:
- m == arrays.length
- $2 <= m <= 10^5$
- 1 <= arrays[i].length <= 500
- $-10^4 <= arrays[i][j] <= 10^4$
- arrays[i] is sorted in ascending order.
- There will be at most $10^5$ integers in all the arrays.
Code
class Solution {
public int maxDistance(List<List<Integer>> arrays) {
int res = 0;
int max = arrays.get(0).get(arrays.get(0).size() - 1);
int min = arrays.get(0).get(0);
for (int i = 1; i < arrays.size(); i++) {
int start = arrays.get(i).get(0);
int end = arrays.get(i).get(arrays.get(i).size() - 1);
res = Math.max(res, Math.abs(max - start));
res = Math.max(res, Math.abs(end - min));
max = Math.max(max, end);
min = Math.min(min, start);
}
return res;
}
}
按 <- 键看上一题!
623. Add One Row to Tree
按 -> 键看下一题!
625. Minimum Factorization