ID | Title | Difficulty | |
---|---|---|---|
Loading... |
70. Climbing Stairs
Easy
LeetCode
Math, Dynamic Programming, Memoization
Problem
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
Code
class Solution {
public int climbStairs(int n) {
if(n <= 0) return 0;
if(n == 1) return 1;
if(n == 2) return 2;
int[] dp = new int[n + 1];
dp[0] = 0;
dp[1] = 1;
dp[2] = 2;
for(int i = 3; i <= n; i++){
dp[i] = dp[i - 1] + dp[i - 2];
}
return dp[n];
}
}
按 <- 键看上一题!
69. Sqrt(x)
按 -> 键看下一题!
71. Simplify Path