ID | Title | Difficulty | |
---|---|---|---|
Loading... |
710. Random Pick with Blacklist
Hard
LeetCode
Array, Hash Table, Math, Binary Search, Sorting, Randomized
Problem
You are given an integer n
and an array of unique integers blacklist
. Design an algorithm to pick a random integer in the range [0, n - 1]
that is not in blacklist
. Any integer that is in the mentioned range and not in blacklist
should be equally likely to be returned.
Optimize your algorithm such that it minimizes the number of calls to the built-in random function of your language.
Implement the Solution
class:
Solution(int n, int[] blacklist)
Initializes the object with the integer n and the blacklisted integersblacklist
.int pick()
Returns a random integer in the range[0, n - 1]
and not inblacklist
.
Example 1:
Input
["Solution", "pick", "pick", "pick", "pick", "pick", "pick", "pick"]
[[7, [2, 3, 5]], [], [], [], [], [], [], []]
Output
[null, 0, 4, 1, 6, 1, 0, 4]
Explanation
Solution solution = new Solution(7, [2, 3, 5]);
solution.pick(); // return 0, any integer from [0,1,4,6] should be ok. Note that for every call of pick,
// 0, 1, 4, and 6 must be equally likely to be returned (i.e., with probability 1/4).
solution.pick(); // return 4
solution.pick(); // return 1
solution.pick(); // return 6
solution.pick(); // return 1
solution.pick(); // return 0
solution.pick(); // return 4
Constraints:
- $1 <= n <= 10^9$
- $0 <= blacklist.length <= min(10^5, n - 1)$
- $0 <= blacklist[i] < n$
- All the values of
blacklist
are unique. - At most $2 * 10^4$ calls will be made to
pick
.
Code
Suppose N=10, blacklist=[3, 5, 8, 9], re-map 3 and 5 to 7 and 6.
class Solution {
int range;
HashMap<Integer, Integer> map;
Random rand;
public Solution(int n, int[] blacklist) {
map = new HashMap<>();
rand = new Random();
range = n - blacklist.length;
for (int num : blacklist) {
map.put(num, -1);
}
int curr = n - blacklist.length;
for (int num : blacklist) {
if (num >= range) continue;
while (map.containsKey(curr)) {
curr++;
}
map.put(num, curr++);
}
}
public int pick() {
int next = rand.nextInt(range);
if (map.containsKey(next)) return map.get(next);
return next;
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(n, blacklist);
* int param_1 = obj.pick();
*/
按 <- 键看上一题!
709. To Lower Case
按 -> 键看下一题!
711. Number of Distinct Islands II