ID | Title | Difficulty | |
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825. Friends Of Appropriate Ages
Medium
LeetCode
Array, Two Pointers, Binary Search, Sorting
Problem
There are n
persons on a social media website. You are given an integer array ages
where ages[i]
is the age of the i^th
person.
A Person x
will not send a friend request to a person y
(x != y
) if any of the following conditions is true:
age[y] <= 0.5 * age[x] + 7
age[y] > age[x]
age[y] > 100 && age[x] < 100
Otherwise, x
will send a friend request to y
.
Note that if x
sends a request to y
, y
will not necessarily send a request to x
. Also, a person will not send a friend request to themself.
Return the total number of friend requests made.
Example 1:
Input: ages = [16,16]
Output: 2
Explanation: 2 people friend request each other.
Example 2:
Input: ages = [16,17,18]
Output: 2
Explanation: Friend requests are made 17 -> 16, 18 -> 17.
Example 3:
Input: ages = [20,30,100,110,120]
Output: 3
Explanation: Friend requests are made 110 -> 100, 120 -> 110, 120 -> 100.
Constraints:
n == ages.length
1 <= n <= 2 * 104
1 <= ages[i] <= 120
Code
class Solution {
public int numFriendRequests(int[] ages) {
Map<Integer, Integer> count = new HashMap<>();
for (int age : ages) {
count.put(age, count.getOrDefault(age, 0) + 1);
}
int res = 0;
for (Integer x : count.keySet())
for (Integer y : count.keySet())
if (isSendRequest(x, y)) {
res += count.get(x) * count.get(y);
if (x == y) {
res -= count.get(x);
}
}
return res;
}
private boolean isSendRequest(int x, int y) {
return !(y <= 0.5 * x + 7 || y > x || (y > 100 && x < 100));
}
}
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